A jug was 60% full of water. After 20% of that water is removed the jug contains 192 ml. What is the maximum amount of water (in ml) that the jug could contain.

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Let us say the volume of the jug is V.

It is said that 20% of the 60% filled jug was removed. That means `0.2xx0.6V ` is removed. So the remaining is;

`(1-0.2)xx0.6V = 0.8xx0.6V`

This `0.8xx0.6V` is equal to 192ml.

`0.8xx0.6V = 192`

`V = 192/(0.6xx0.8)`

`V = 400`

*So the volume of the jug is 400ml.*

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