# I invest \$x at 3%/annum & \$y at 4%/ annum.Annual income fm this is \$22. If I invested \$y at 3% & \$x at 4%, my income would be \$20/annum. find x.

enotechris | College Teacher | (Level 2) Senior Educator

Posted on

The idea is to use both equations to solve for one variable and substitute it back for the other. So:

1) .03x + .04y = 22    and

2) .04x + .03y = 20    so combining (adding) equations gives you

3) .07x + .07y = 42    divide each term by .07 to reduce equation

4)  x + y = 600          and set value for y

5)  y = 600 - x

If you substitute 600 - x for y in equation 1, you should find that x = \$200 and y = \$400.

revolution | College Teacher | (Level 1) Valedictorian

Posted on

Let's do simultaneous equations:

0.3x+0.4y=22 -1

0.4x+0.3y=20 -2

Multiply both eqn by 10 to get whole number

3x+4y=220 -3

4x+3y=200 -4

Multiply eqn 3 by 4 and eqn 4 by 3

12x+16y=880 -5

12x+9y=600 -6

eqn5-eqn6

12x-12x+16y-9y= 880-600

7y=280

y=40

sub y=40

12x+9(40)=600

12x+360=600

12x=240

x=20 dollars

We’ve answered 317,831 questions. We can answer yours, too.