What is `int sqrt(3x + 4) dx` ?

### 1 Answer | Add Yours

We have to find `int sqrt(3x + 4) dx`

Let 3x + 4 = y

dy/dx = 3

=> dy/3 = dx

`int sqrt (3x+ 4) dx`

=> `(1/3) int sqrt y dy`

=> (1/3)*y^(3/2)/(3/2)

=> (2/9)*y^(3/2)

substitute y = 3x + 4

=> (2/9)*(3x + 4)^(3/2)

**The required integral is (2/9)*(3x + 4)^(3/2)**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes