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Integrate: `int` `(sqrt(x)/(x^2+x))` ` ` ` ` ` `
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`x = tan^2t`
`dx = 2tantsec^2tdt`
`= 2t+C` Where C is a constant.
So the answer is `intsqrtx/(x^2+x)dx = 2tan^(-1)sqrtx+C`
Posted by jeew-m on July 17, 2013 at 1:07 AM (Answer #1)
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