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`int(dz/sqrt(z))` indefinite integral

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jjmgingrich | Student, Undergraduate | Salutatorian

Posted July 30, 2013 at 5:21 PM via web

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`int(dz/sqrt(z))`

indefinite integral

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aruv | High School Teacher | Valedictorian

Posted July 30, 2013 at 5:38 PM (Answer #1)

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`int1/sqrt(z)dz=int(z)^(-1/2)dz`

`=z^(-1/2+1)/(-1/2+1)+c`

`=z^(1/2)/(1/2)+c`

`=2z^(1/2)+c`

where c is integrating constant.

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