Indicate at what temperature the two reactions will be spontaneous  PCl_3 (g) + Cl_2 (g) --> PCl_5 (g)   ΔH° = -97.9 kJ NH_4 CO_2 NH_2 (s) = 2NH_3 (g) + CO_2 (g)   ΔH° = + 159.2 kJ

llltkl | College Teacher | (Level 3) Valedictorian

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The thermodynamic requirement for spontaneity of a reaction is that the reaction must have a negative value of Gibbs’ free energy (∆G°). According to the definition of free energy, ∆G° = ∆H° – T∆S° where the terms have their usual significance.

For the first reaction, ∆H° is negative, ∆S° is negative as there are lesser number of gaseous molecules in the product side, compared to the reactant side. In order to make ∆G° negative, the first term must surpass the second term. Or, ∆H° > T∆S°

Or, T < ∆H°/∆S°.

Similarly, for the second reaction, ∆H° is positive, ∆S° is also positive as there is greater number of gaseous molecules in the product side, compared to the reactant side. So, in order to make ∆G° negative, the second term must surpass the first term here. In other words,

∆H° < T∆S° or, T > ∆H°/∆S°. Hence the reactions will be spontaneous at temperatures at which the above two criteria are fulfilled.

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