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Find `dy/dx` for cos(y^2) + x = e^y
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The derivative `dy/dx` has to be determined for `cos(y^2) + x = e^y`
Using implicit differentiation gives:
`-sin(y^2)*2y*(dy/dx) + 1 = e^y*(dy/dx)`
=> `(dy/dx)*(e^y + sin(y^2)*2y) = 1`
=> `dy/dx = 1/(e^y + sin(y^2)*2y)`
The derivative `dy/dx` for the expression `cos(y^2) + x = e^y` is `dy/dx = 1/(e^y + sin(y^2)*2y)`
Posted by justaguide on March 13, 2012 at 11:13 PM (Answer #1)
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