# How would you write the equation if the problem has X-intercept=6 and Y=intercept= 2

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Given the x-intercept is 6.

We know that the x-intercept is the point that intersect with the x-axis.

The point intersect with the x-axis at x= 6, then the value of y is 0.

Then the point ( 6, 0) is on the graph.

We are also given the y-intercept = 2.

Then, the line intersect with the y-axis at y= 2, then the value of x is 0.

Then, the point ( 0, 2) is on the graph.

Now we have two points on the graph ( 6, 0) and (0, 2)

Now we will determine the equation of the lines.

We will calculate the slops.

==> m = (y2-y1)/(x2-x1)

==> m= ( 2/6 = 1/3

==> Now we will write the equation of the line.

==> y-y1 = m (x-x1)

==> y - 0 = (1/3) ( x -6)

**==> y= (1/3)x - 2**