How would I find the Vertex of this equation?

How would I find the Vertex of this equation?

2x2-12x+16

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The equation is,

`y = 2x^2-12x+16`

let's transform this to this format,

`y = a(x-h)^2+k`

Where (h,k) is the vertex of the equation.

`y = 2(x^2-6x+8)`

`y = 2(x^2-6x+3^2 - 3^2+8)`

`y = 2((x^2-2*(3x)+3^2) - 9+8)`

`y = 2((x-3)^2 - 1)`

`y = 2(x-3)^2 - 2`

therefore the vertex is (3,-2).

`2x^2-12x+16`

`a=2` `b=-12` `c=16`

`-b/(2a)`

`x=12/(2(2))` `x=12/4 ` `x=3`

plug in x

`y=2(3)^2-12(3)+16`

`y= 2(9)-36+16`

`y= 18-36+16`

`18-36=-18+16=-2`

`y=-2`

the vertex is` (3,-2)`

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