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# How would I find the Vertex of this equation?How would I find the Vertex of this...

skyler89 | Student, College Sophomore | Honors

Posted April 29, 2012 at 1:16 PM via web

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How would I find the Vertex of this equation?

How would I find the Vertex of this equation?

2x2-12x+16

thilina-g | College Teacher | (Level 1) Educator

Posted April 29, 2012 at 1:26 PM (Answer #1)

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The equation is,

`y = 2x^2-12x+16`

let's transform this to this format,

`y = a(x-h)^2+k`

Where (h,k) is the vertex of the equation.

`y = 2(x^2-6x+8)`

`y = 2(x^2-6x+3^2 - 3^2+8)`

`y = 2((x^2-2*(3x)+3^2) - 9+8)`

`y = 2((x-3)^2 - 1)`

`y = 2(x-3)^2 - 2`

therefore the vertex is (3,-2).

atyourservice | Student , Grade 10 | eNoter

Posted February 22, 2014 at 4:52 PM (Answer #2)

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`2x^2-12x+16`

`a=2`  `b=-12`  `c=16`

`-b/(2a)`

`x=12/(2(2))`    `x=12/4 `       `x=3`

plug in x

`y=2(3)^2-12(3)+16`

`y= 2(9)-36+16`

`y= 18-36+16`

`18-36=-18+16=-2`

`y=-2`

the vertex is` (3,-2)`

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