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How would I find the Vertex of this equation?How would I find the Vertex of this...
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The equation is,
`y = 2x^2-12x+16`
let's transform this to this format,
`y = a(x-h)^2+k`
Where (h,k) is the vertex of the equation.
`y = 2(x^2-6x+8)`
`y = 2(x^2-6x+3^2 - 3^2+8)`
`y = 2((x^2-2*(3x)+3^2) - 9+8)`
`y = 2((x-3)^2 - 1)`
`y = 2(x-3)^2 - 2`
therefore the vertex is (3,-2).
Posted by thilina-g on April 29, 2012 at 1:26 PM (Answer #1)
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