# How will you make 37 with five(5) fives(5).

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The given question requires the creation of an expression which has only the number 5 in it and we can use 5 only 5 times. As there is no constraint on the operations that can be used, a possible solution which satisfies the requirements is the expression: (5*5)+(5!/(5+5)).

Here 5! is the factorial of 5 which is 5*4*3*2*1=120.

Solving the expression we can see that:

(5*5)+(5!/(5+5))

=25+(5!/(5+5)

=25+(120/10)

=25+12

=37

Therefore the expression** (5*5)+(5!/(5+5)) **yields 37 using only the number 5 and restricting ourselves to only 5 instances of the number 5.

We can use 5 five times 5 and get 37 as follows:

37 = 5*5+ 5+5+[sqrt5].

As 5*5 = 25

5+5 = 10.

[sqrt5] means integral part of sqrt5 = integral part of (2.2.23606798...) = 2.

Therefore, 5*5+5+5 + integral part of (sqrt5) = 25+10+2 = 37.