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How to verify the trig identity sec^(2)x/secx-1=[csc^(2)x](secx-1)?I've tried...
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High School Teacher
I think there is an error in your problem the LHS should be +1 not -1
Posted by rcmath on May 14, 2012 at 10:49 PM (Answer #1)
I'm pretty sure that the equation should look like this:
sec²x/secx-1 = csc²x(secx+1)
I think you switched the signs on each side of the equation, but I might not have written the equation down correctly. Thanks for your help!
Posted by sputnik77 on May 14, 2012 at 11:25 PM (Answer #2)
I just realized that I originally posted the original equation wrong! The right one is the one that I just posted. Oops!
Posted by sputnik77 on May 14, 2012 at 11:29 PM (Answer #3)
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