How to verify the trig identity sec^(2)x/secx-1=[csc^(2)x](secx-1)?I've tried converting the secants to 1/cosines but that doesn't seem to be getting me anywhere.  Thanks for your help!



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rcmath's profile pic

Posted on (Answer #1)

I think there is an error in your problem the LHS should be +1 not -1




***LHS `(sec^2x)/(secx+1)=(1/(cos^2x))/(1/cosx+1)=`







sputnik77's profile pic

Posted on (Answer #2)

I'm pretty sure that the equation should look like this:


sec²x/secx-1 = csc²x(secx+1)

I think you switched the signs on each side of the equation, but I might not have written the equation down correctly.  Thanks for your help!

sputnik77's profile pic

Posted on (Answer #3)

I just realized that I originally posted the original equation wrong!  The right one is the one that I just posted.  Oops!

rcmath's profile pic

Posted on (Answer #4)

If you repeat the above mentioned steps, change the -1 into +1 in the RHS and +1 to -1 in the LHS, you should get the solution to yor problem.

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