how to solve for x by determining a common base

`3^(n+4)=27^(2n)`

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Solve `3^(n+4)=27^(2n)` :

(1) Recognize that `27=3^3`

(2) Rewrite both sides with base 3:

`3^(n+4)=(3^3)^(2n)`

`3^(n+4)=3^(6n)`

(3) Since the bases are the same, the exponents must be the same so:

`n+4=6n`

`4=5n`

`n=4/5`

**So the solution is n=4/5**

Checking we get `3^(4/5+4)=27^(8/5)~~195.066199508`

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