how to solve for x by determining a common base `3^(n+4)=27^(2n)`  



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Posted on (Answer #1)

Solve `3^(n+4)=27^(2n)` :

(1) Recognize that `27=3^3`

(2) Rewrite both sides with base 3:



(3) Since the bases are the same, the exponents must be the same so:




So the solution is n=4/5

Checking we get `3^(4/5+4)=27^(8/5)~~195.066199508`


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