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How  I solve:  `4*log_a 6-3*log_a 5-4*log_a 2` =

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monique06 | Valedictorian

Posted June 6, 2013 at 4:33 PM via web

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How  I solve:  `4*log_a 6-3*log_a 5-4*log_a 2` =

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted June 6, 2013 at 5:00 PM (Answer #1)

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The expression 4*log_a 6 -3log_a 5 - 4*log_a 2 has to be simplified.

Use the property a*log b = log b^a, log a+ log b = log(a*b) and log a - log b = log(a/b)

`4*log_a 6 -3log_a 5 - 4*log_a 2`

= `log_a 6^4 - log_a 5^3 - log_a 2^4`

= `log_a (6^4/(5^3*2^4))`

= `log_a (81/125)`

The required result is `log_a (81/125)`

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