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How much work must be done to stop a 1800 kg vehicle travelling at 30m/s???
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If we should stop the vehicle we should make its kinetic energy zero. That means we have to do a work equal to its kinetic energy against its motion.
Therefore work done `= W`
`W = K_E`
`W = 1/2 mv^2`
`W = 1/2 xx 1800 xx 30^2 J`
`W = 900 xx 900 J`
`W = 810000 J`
`W = 810 kJ`
Therefore the work we have to in order to stop the vehicle is 810 kJ.
Posted by thilina-g on June 1, 2012 at 7:20 AM (Answer #1)
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