# how many values of x insatisfy 2sin(1/2x)=cos(2x)?

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We need to find the values of x in [0, 2*pi] that satisfy 2*(sin x/2) = cos 2x.

sin (x/2) = sqrt [(1 - cos x)/2]

cos 2x = 2*(cos x)^2 - 1

As 2*(sin x/2) = cos 2x

=> 2*sqrt [(1 - cos x)/2] = 2*(cos x)^2 - 1

take the square of both the sides

=> 4*(1 - cos x)/2 = 4*(cos x)^4 + 1 - 4*(cos)^2

=> 2 - 2*cos x = 4*(cos x)^4 + 1 - 4*(cos)^2

=> 4*(cos x)^4 - 4*(cos)^2 + 2*cos x - 1 = 0

We see that cos x has a highest power of 4. This gives us 4 values of cos x that we can get from solving the equation. Also, for each value of cos x, there are two values of x that give the same value of cos x.

**This gives 8 values of x that can satisfy the given equation.**