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How many solutions are there to eq x^2-13=0?
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Since the number of solutions to a polynomial equation is equal to the highest power of variable `x` , yields that the number of solutions to a quadratic equation is maximum 2, either both reals, or both imaginaries.
You should solve the equation to prove that there exists two real solutions, such that:
`x^2 - 13 = 0 => x^2 = 13 => x_(1,2) = +-sqrt 13`
Hence, evaluating the number of solutions to the quadratic equation yields that there exists two real solutions, `x = sqrt 13, x = -sqrt 13.`
Posted by sciencesolve on July 4, 2013 at 4:37 PM (Answer #1)
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