How many S atoms are there in 0.5 mole of S_3?

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NOw in S3, 1 mol of S3 has 3 mole of S3 atoms. And we know that

1 mole of any substance = 6.023*10^23 substance

so 0.5 mol S3 would be

0.5 mol S3 * (3 atoms of S / 1mol S3)*(6.023*10^23 atoms of S/1 mole of S)

**9.03*10^23 atoms of S**

1 mole of S3 has avogadro number of atoms = 6.023 * 10^23.

So for 0.5 mole of S3 it would be

0.5 * 6.023 * 10^23 = 3.0115 × 10^23 atoms.

But in one S3 molecule there are 3 atoms so total number of s atoms in s3 would be....

(3)(3.0115 × 10^23) = 9.0345 × 10^23.

9.0345 × 10^23 atoms of S are present in 0.5 moles of S3.

Can also be done in other way...

Following the T table method

0.5 moles of S3 * (3 atoms of S/1 mole of S3) = 1.5 atoms of S

1.5 atoms of S * 6.023 * 10^23 = 9.0345 × 10^23 atoms of S.

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