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How many moles of oxygen gas would be produced if: 0.8 moles of potassium chlorate...

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user1191221 | (Level 1) Honors

Posted May 27, 2013 at 2:15 AM via web

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How many moles of oxygen gas would be produced if:

0.8 moles of potassium chlorate (KClO3) is decomposed by heating, and breaks down into potassium chloride and oxygen?

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llltkl | College Teacher | (Level 3) Valedictorian

Posted May 27, 2013 at 2:32 AM (Answer #1)

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Potassium chlorate (KClO3) decomposes upon heating, with or without a catalyst, to produce potassium chloride and oxygen. The balanced chemical equation for the decomposition of KClO3 is:

2KClO3 → 2KCl + 3O2

From the stoichiometry of the reaction, it can be said that

When 2 moles of KClO3 is decomposed, number of moles of oxygen produced is 3

Therefore, when 0.8 moles of KClO3 is decomposed, number of moles of oxygen produced will be = 3*0.8/2 = 1.2

Hence, 1.2 moles of oxygen would be produced from 0.8 moles of KClO3.

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