How many moles of oxygen gas would be produced if:
0.8 moles of potassium chlorate (KClO3) is decomposed by heating, and breaks down into potassium chloride and oxygen?
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Potassium chlorate (KClO3) decomposes upon heating, with or without a catalyst, to produce potassium chloride and oxygen. The balanced chemical equation for the decomposition of KClO3 is:
2KClO3 → 2KCl + 3O2
From the stoichiometry of the reaction, it can be said that
When 2 moles of KClO3 is decomposed, number of moles of oxygen produced is 3
Therefore, when 0.8 moles of KClO3 is decomposed, number of moles of oxygen produced will be = 3*0.8/2 = 1.2
Hence, 1.2 moles of oxygen would be produced from 0.8 moles of KClO3.
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