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How many moles of Na3C6H5O7 can be produced if one tablet containing 0.0267 mol of...

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hannahbannna | Student, Grade 10 | eNoter

Posted May 18, 2011 at 2:06 PM via web

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How many moles of Na3C6H5O7 can be produced if one tablet containing 0.0267 mol of NaHCO3 is dissolved?
When an antacid tablet dissolves in water, the fizz is due to a reaction between sodium hydrogen carbonate (sodium bicarbonate, NaHCO3) and citric acid (H3C6H5O7).
3 NaHCO3(aq) + H3C6H5O7(aq) 3 CO2(g) + 3 H2O(l) + Na3C6H5O7(aq)
Thanks! If you could at least show some of your work that would be great so I can figure out how to solve future problems like this. Thank you so much!

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted May 18, 2011 at 5:28 PM (Answer #1)

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To solve this problem look at the equation of the chemical reaction that takes place between the antacid which is sodium bicarbonate and citric acid:

3 NaHCO3 + H3C6H5O7 --> 3 CO2 + 3 H2O + Na3C6H5O7

We see that 3 molecules of NaHCO3 react with one molecule of citric acid to give one molecule of sodium citrate or Na3C6H5O7 in the final products.

When one tablet of NaHCO3  containing 0.0267 mole of the compound reacts with citric acid the number of moles of Na3C6H5O7 produced is one third the number of moles of NaHCO3 that reacted originally.

This is equal to 0.0267/3 = 0.0089 moles

When 0.0267 moles of NaHCO3 are dissolved we get 0.0089 moles of Na3C6H5O7.

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