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How many moles of H2SO4 will react with 18 mol of Al in a chemical reaction involving...
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First we will need to the complete chemical reaction involving sulfuric acid and alluminium.
2Al + 3H2SO4 -----> Al2(SO4)3 + 3H2
From the reaction
2 moles of Al react with 3 moles of H2SO4 [ That is is 2:3 ratio]
18 moles of Al will react with 27 moles of H2SO4.
(18 * 3)/2 = 27 moles of H2SO4.
Therefore 18 moles of Al will require 27 moles of H2SO4 to react.
Posted by sanjeetmanna on June 18, 2012 at 7:34 PM (Answer #1)
You should write the chemical reaction and you need to balance the equation such that:
Al + H_2SO_4 -> Al_2(SO_4)_3 + H_2
You need to balance the group SO_4, hence, you should multiply by 3 to the left such that:
Al + 3H_2SO_4 -> Al_2(SO_4)_3 + H_2
You need to balance Al and H2, hence, you should multiply Al by 2, to the left, and you need to multiply H_2 by 3 such that:
2Al + 3H_2SO_4 -> Al_2(SO_4)_3 + 3H_2
You need to determine the mole ratio of H_2SO_4 to Al, hence, the mole ratio is of 2:3.
2 moles of Al reacts with 3 moles of H_2SO_4
18 moles of Al reacts with x moles of H_2SO_4
Hence, x = 18*3/2 = 9*3 = 27 moles of H_2SO_4
Hence, evaluating the number of moles of H_2SO_4 that reacts with 18 moles of Al yields 27 moles.
Posted by sciencesolve on June 30, 2012 at 5:15 PM (Answer #2)
Aluminum reacts with `H_2SO_4` to form `Al_2(SO_4)_3` . The equation of the chemical reaction is:
`2Al + 3H_2SO_4 -> Al_2(SO_4)_3 + 3H_2 `
2 moles of aluminum react with 3 moles of hydrogen sulfide. 18 moles of Al will react with (18/2)*3 = 27 moles of hydrogen sulfide.
18 moles of aluminum react with 27 moles of hydrogen sulfide in the reaction involving the two.
Posted by justaguide on June 21, 2012 at 4:50 PM (Answer #4)
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