How many moles of H2SO4 will react with 18 mol of Al in a chemical reaction involving the two.

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First we will need to the complete chemical reaction involving sulfuric acid and alluminium.

2Al + 3H2SO4 -----> Al2(SO4)3 + 3H2

From the reaction

2 moles of Al react with 3 moles of H2SO4 [ That is is 2:3 ratio]

So

18 moles of Al will react with 27 moles of H2SO4.

SOLUTION:-

(18 * 3)/2  = 27 moles of H2SO4.

Therefore 18 moles of Al will require 27 moles of H2SO4 to react.

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Aluminum reacts with `H_2SO_4` to form `Al_2(SO_4)_3` . The equation of the chemical reaction is:

`2Al + 3H_2SO_4 -> Al_2(SO_4)_3 + 3H_2 `

2 moles of aluminum react with 3 moles of hydrogen sulfide. 18 moles of Al will react with (18/2)*3 = 27 moles of hydrogen sulfide.

18 moles of aluminum react with 27 moles of hydrogen sulfide in the reaction involving the two.

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You should write the chemical reaction and you need to balance the equation such that:

Al + H_2SO_4 -> Al_2(SO_4)_3 + H_2

You need to balance the group SO_4, hence, you should multiply by 3 to the left such that:

Al + 3H_2SO_4 -> Al_2(SO_4)_3 + H_2

You need to balance Al and H2, hence, you should multiply Al by 2, to the left, and you need to multiply H_2 by 3 such that:

2Al + 3H_2SO_4 -> Al_2(SO_4)_3 + 3H_2

You need to determine the mole ratio of H_2SO_4 to Al, hence, the mole ratio is of 2:3.

2 moles of Al reacts with 3 moles of H_2SO_4

18 moles of Al reacts with x moles of H_2SO_4

Hence, x = 18*3/2 = 9*3 = 27 moles of H_2SO_4

Hence, evaluating the number of moles of H_2SO_4 that reacts with 18 moles of Al yields 27 moles.