How many moles of CaCl2 are in 250mL of a 3.0M of CaCl2 solution?

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sciencesolve's profile pic

Posted on

Since the problem provides the amount in liters of CaCl2 solutions, then 3.0M expresses the molarity of solution, hence you need to use the molarity formula such that:

M = (number of moles of CaCl2 solution)/(volume of CaCl2 in liters)

You need to convert the amount of 250 mL in liters such that:

250mL = 250*10^(-3)L

Substituting 3 for M and 250*10^(-3)L for V yields:

3 = N/(0.250) => N = 3*0.250

N = 0.75

Hence, evaluating the number of moles in 250mL of CaCl2 solution yields 0.75 moles.

Top Answer

guavamangoes's profile pic

Posted on

3.0 M = 3moles/1liter

250mL= 0.25 L

so, 3mol/1L= (?)mol/.25L

there are 0.75 moles of CaCl2 in 250 mL of a 3.0 molar solution

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