How many grams of Zn will be produced from 3.00 mol of Ca in the following reaction: Ca + ZnCO3 → CaCO3 + Zn
2 Answers | Add Yours
The reaction between calcium and zinc carbonate leads to the formation of calcium carbonate and zinc. The chemical equation of the reaction is:
Ca + ZnCO3 --> CaCO3 + Zn
In the reaction one mole of Ca reacts with one mole of ZnCO3 to give one mole of CaCO3 and one mole of Zn. 3 moles of Ca will yield 3 moles of Zn. The molar mass of zinc is 65.38. 3 moles of zinc have a mass of 196.14 g.
When 3 moles of Ca take part in the reaction represented by: Ca + ZnCO3 --> CaCO3 + Zn, 196.14 g of zinc is produced.
First balance the given reaction.
This reaction is balanced
Ca + ZnCO3---> CaCO3 + Zn.
Given is 3 moles of Ca.
So now we have to find that how many moles of Zn is formed when 3 moles of Ca is reacting.
From the reaction we can see that they are in the 1:1 ratio that means one mole of Ca give rise to one mole of Zn.
So 3 moles of Ca will give rise to 3 moles of Zn.
Now we are asked to find the mass.
We got 3 moles of Zn.
Moles = mass / molar mass.
Mass = Moles * Molar Mass
Mass = 3 mole * 65.39 gm/mole
Mass = 196.17 gm.
Therefore when 3 mole of Ca is reacting 196.17 gm of Zn is formed.
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes