How to find the intersection of line y=12x+8 with axis?

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We know that when a line is intersecting x axis, the value of x is the solution of the equation.

We'll have the equation of the line y = 12x+8 (1).

12x+8 = 0 (2)

x = -8/12

x = -2/3

Comparing (1) and (2), we'll get y = 0.

So, the line is intercepting x axis in the point (-2/3 , 0).

We'll conclude that if we want to find out the y intercepting point, we'll have to put x = 0.

y = 12x+8

For x = 0 => y = 12*0 + 8

y = 8

**Therefore, the line is intercepting x axis in the point (-2/3 , 0) and the line is intercepting y axis in the point (0 , 8).**

The equation of a line in the form x/a + y/b = 1 gives the x and y intercepts as a and b

The line we have is y = 12x + 8

y = 12x + 8

=> y - 12x = 8

divide all the terms by 8

=> -12x/8 + y/8 = 1

=> x/(-8/12) + y/8 = 1

The x intercept is -8/12 and the y-intercept is 8.

**The line has an intersection with the x-axis at (-8/12, 0) and with the y-axis at (0,8)**

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