How to find the intersection of line y=12x+8 with axis?
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We know that when a line is intersecting x axis, the value of x is the solution of the equation.
We'll have the equation of the line y = 12x+8 (1).
12x+8 = 0 (2)
x = -8/12
x = -2/3
Comparing (1) and (2), we'll get y = 0.
So, the line is intercepting x axis in the point (-2/3 , 0).
We'll conclude that if we want to find out the y intercepting point, we'll have to put x = 0.
y = 12x+8
For x = 0 => y = 12*0 + 8
y = 8
Therefore, the line is intercepting x axis in the point (-2/3 , 0) and the line is intercepting y axis in the point (0 , 8).
The equation of a line in the form x/a + y/b = 1 gives the x and y intercepts as a and b
The line we have is y = 12x + 8
y = 12x + 8
=> y - 12x = 8
divide all the terms by 8
=> -12x/8 + y/8 = 1
=> x/(-8/12) + y/8 = 1
The x intercept is -8/12 and the y-intercept is 8.
The line has an intersection with the x-axis at (-8/12, 0) and with the y-axis at (0,8)
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