How do you solve this? Write the standard form of the equation of a circle with center (0, 0), given r = 8.
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The equation of a circle with the center in M(a,b)=O(0,0) and r=8
The standard form of a circle's equation with (-g,-f) as centre is :
The equation of the given circle with centre (0,0) and with radius 8 is (x-0)^2+(y-0)^2 =8^2.
Rearranging the equation, we get:
x^2+ y^2+2*0*x+2*0*y+(-64)=0, in standard form with g=0, f=0 and c=-64.
The simplified form is: x^2+y^2-64=0.
Hope this helps.
The general formula for equation of circles is:
(x-a)^2+(y-b)^2=r^2, in the standard form, where (a,b) is the centre and r is the radius.
Since centre is (0,0) and raidus=8
Sub numerals into equation
(x-0)^2 + (y-0)^2= (8)^2
the equation of the circle with centre at the origin is given by
therefore, our equation becomes
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