How do you solve this exponential equation for the variable?:
My teacher told me to use natural log: ln
My teacher also told me to use log base: I guess that is e
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We can use the property:
`1/a^m = a^-m`
We will have:
`3^(r - 3) = 3^-1`
Take the natural logarithm of both sides.
`ln3^(r - 3) = ln3^-1`
Use the property: `lna^b = blna`
` ``(r - 3)ln3 = -1ln3 `
Divide both sides by ln3.
`r - 3 = -1`
Add 3 on both sides.
`r = 2`
Therefore, the answer is r = 2.
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