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How do you solve this exponential equation for the variable?: 3^r-3= 1/3 My teacher...
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High School Teacher
We can use the property:
`1/a^m = a^-m`
We will have:
`3^(r - 3) = 3^-1`
Take the natural logarithm of both sides.
`ln3^(r - 3) = ln3^-1`
Use the property: `lna^b = blna`
` ``(r - 3)ln3 = -1ln3 `
Divide both sides by ln3.
`r - 3 = -1`
Add 3 on both sides.
`r = 2`
Therefore, the answer is r = 2.
Posted by violy on May 5, 2013 at 12:38 AM (Answer #1)
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