# How do you simplify this: 2x/3 * x^3/6x-9 / x^2/9? The little arrow (^) means the square root.

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`((2x)/3)* (x^3/(6x - 9))-: (x^2/9)`

factor 6x - 9 to 3(2x - 3); multiply by the reciprocal of `x^2/9`

` ` `((2x)/3)* (x^3/(3(2x-3)))*(9/x^2)`

` `cancel the 2 three's with the 9; cancel x^2 with x^3 leaving an x:

you'll now have:

`(2x)* (x/(2x-3))`

**multiply through gives you:**

`(2x^2)/(2x - 3)`

` `