How do you simplify 2/y+2 - 1/y+3 + 5/y-1

### 1 Answer | Add Yours

`2/(y+2)-1/(y+3)+5/(y-1)`

`= (2(y+3)(y-1)-(y+2)(y-1)+5(y+2)(y+3))/((y+2)(y+3)(y-1))`

`= (2(y^2+2y-3)-(y^2+y-2)+5(y^2+5y+6))/((y+2)(y+3)(y-1))`

`= (2y^2+4y-6-y^2-y+2+5y^2+25y+30)/((y+2)(y+3)(y-1))`

`= (6y^2+28y+26)/((y+2)(y+3)(y-1))`

`= (2(3y^2+14y+13))/((y+2)(y+3)(y-1))`

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