How do you find the volume of an uneven figure made up of 1 inch cubes?

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There are a couple of approaches that you can use to find the volume of an irregular figure:

Technically, one finds the volume by multiplying a figure’s (length x width x height). In the case of an irregular figure, one cannot determine volume using the formula. But, if the diagram you have shows the faces of the individual cubes, then you can count the cubes that you see, plus the ones that you expect to be behind the cubes facing you based on how the diagram is drawn.

Another approach is to look at the irregular figure as if it is a bunch of regular figures that have been put together. In this case, use the (length x width x height) formula to solve for the volume of all the regular figures, then add the volumes together to get the volume of the irregular figure.

For either approach, your units will still be in.3

First, count the cubes that are there. Then, draw in the missing cubes. Count those. Now, subtract the numer of drawn-in cubes from the main number of cubes. There's your answer! :)

*You can also divide the cube into two sections. Then find the length width and height of each divided cube. Add them together and there you go. o:-)*

**(halo)**

Just measure the length, breadth and height of one cube. Count the number of cubes in the figure. Calculate the volume of one cube first before multiplying it with the total amount of cubes in the uneven figure. That would give you the total volume.

use the volume formula length x width x height, for one cube and then count the amounts of cubes and multiply it by the volume of one cube.

To clarify, the last thing in the previous answer was that your answer will be in 'inches cubed' or in^3

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