How do you factorize?

(x-3)^2 - (x+4)^2

### 1 Answer | Add Yours

We know that;

`A^2-B^2 = (A+B)(A-B)`

Let;

`A = (x-3)`

`B = (x+4)`

`(x-3)^2-(x+4)^2`

`= A^2-B^2`

`= (A+B)(A-B)`

`= (x-3+x+4)(x-3-(x+4))`

`= (2x+1)(-7)`

`= -7(2x+1)`

**So the answer is;**

`(x-3)^2-(x+4)^2 = -7(2x+1)`

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