# How do you factor 25b^2-60B+36?

mwmovr40 | College Teacher | (Level 1) Associate Educator

Posted on

Sorry... I forgot to do the Quadratic Formula method:

assume  ﻿﻿﻿`25B^2 -60B + 36 =0`

`B = (-b +- sqrt(b^2 - 4ac))/(2a)`  where a = 25, b = -60, and c = 36

`B = (60 +- sqrt(3600 - 3600))/(50) = 60/50 = 6/5`  so, putting this into factors:

`(B - 6/5)(B-6/5) = (B - 6/5)^2 = (5B - 6)^2﻿`

mwmovr40 | College Teacher | (Level 1) Associate Educator

Posted on

There are a couple of ways of factoring this polynomial.  Brute force and the Quadratic Formula.

By brute force, you need to find factors of 25 and of 36 that will combine to form -60.

Factors of 25                               factors of 36

1, 25                                           1, 36

5, 5                                             2, 18

3,  12

4,   9

6,   6

To get the signs to work our right, we would need for the factors to have subtraction.

Guess 1:

`(5B - 4)(5B - 9) = 25B^2 - 45B - 20B +36 = 25B^2 -65B +36`

Gues 2:

`(5B - 6)(5B -6) = 25B^2 - 30B - 30B + 36 = 25B^2 -60B + 36` as desired.

atyourservice | Student, Grade 11 | (Level 3) Valedictorian

Posted on

`25b^2-60B+36  `

find the square root of a and c

`(5b+6)^2 `

`sqrt((5b+6)^2) `

`5b+6`

is the answer but to solve faster set it equal to 0

5b+6=0

`5b=-6`

`b=-6/5`

or

`-1 1/5`