How do you factor 125 + y^6?

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Posted on

`y^6+125`

rule:  `a^3+b^3=(a+b)(a^2-ab+b^2)`

`a = y^2` because `(y^2)^3 = y^6`

`5^3 = 125`

thus:

`(y^2+5)(y^4-5y^2+25)`

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