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Factorize: y^3 - 1
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we know a^3-b^3=(a-b)(a^2+b^2+ab)
here a=y and b=1 ,so we have
Posted by pramodpandey on March 22, 2013 at 6:33 AM (Answer #1)
To factorize `y^3 - 1` use the relation `a^3 - b^3 = (a - b)*(a^2 + ab + b^2)`
Substitute a^3 with y^3 and b^3 with 1 = 1^3. This gives:
y^3 - 1
= y^3 - 1^3
= (y - 1)(y^2 + y + 1)
The factorized form of y^3 - 1 is (y - 1)(y^2 + y + 1)
Posted by justaguide on March 22, 2013 at 6:36 AM (Answer #2)
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