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Factorize: y^3 - 1  

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mattlimey | Student, Grade 11 | Honors

Posted March 22, 2013 at 6:27 AM via web

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Factorize: y^3 - 1

 

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pramodpandey | College Teacher | Valedictorian

Posted March 22, 2013 at 6:33 AM (Answer #1)

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we know a^3-b^3=(a-b)(a^2+b^2+ab)

here a=y and b=1 ,so we  have

y^3-1=(y-1)(y^2+1+y)

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted March 22, 2013 at 6:36 AM (Answer #2)

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To factorize `y^3 - 1` use the relation `a^3 - b^3 = (a - b)*(a^2 + ab + b^2)`

Substitute a^3 with y^3 and b^3 with 1 = 1^3. This gives:

y^3 - 1

= y^3 - 1^3

= (y - 1)(y^2 + y + 1)

The factorized form of y^3 - 1 is (y - 1)(y^2 + y + 1)

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atyourservice | Student, Grade 10 | Valedictorian

Posted February 23, 2014 at 5:47 AM (Answer #3)

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`y^3 - 1`

`(y-1)(y^2+y+1)`

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