# How do I write y=2/3x-4/5 in standard form; And how do I find the equation of the line with a slope -1/2 and passing through (3,-1)? Thank you

### 1 Answer | Add Yours

y= 2/3 x - 4/5

To write in the standars form we will ultiply by 15.

==> 15y = 10x - 12

==> 15y - 10x + 12 = 0

Now we need to find the line with slope m= -1/2 and passes through the point (3,-1)

==> y-y1 = m (x-x1)

==> y+1 = -1/2 (x-3)

==> y= -1/2 x + 3/2 - 1

==> y= -1/2 x + 1/2

Now to write into standard form we will multply by 2.

==> 2y = -x + 1

==> 2y + x - 1 = 0