How do I write y=2/3x-4/5 in standard form; And how do I find the equation of the line with a slope -1/2 and passing through (3,-1)? Thank you

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hala718 | High School Teacher | (Level 1) Educator Emeritus

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y= 2/3 x - 4/5

To write in the standars form we will  ultiply by 15.

==> 15y = 10x - 12

==> 15y - 10x + 12 = 0

Now we need to find the line with slope m= -1/2 and passes through the point (3,-1)

==> y-y1 = m (x-x1)

==> y+1 = -1/2 (x-3)

==> y= -1/2 x + 3/2 - 1

==> y= -1/2 x + 1/2

Now to write into standard form we will multply by 2.

==> 2y = -x + 1

==> 2y + x - 1 = 0

 

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