# How do I solve this problem? (x+2)(x-1)-(2 x+5)=-7

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The equation to be solved is : (x+2)(x-1)-(2x+5)=-7

(x+2)(x-1)-(2x+5)=-7

open the brackets

=> x^2 - x + 2x - 2 - 2x - 5 = -7

=> x^2 - x -7 = -7

=> x^2 - x = 0

=> x(x - 1) = 0

=> x = 0 and x = 1

**The solution of the equation is x = 1 and x = 0**

I think this did help. I have solved it a few times but I am gonna give it a break and see if I can still do it.

Well, first you simplify the equation:

(x^2+x-2)-(2x+5)=-7

x^2-x-7=-7

Then by using the Addition Property of Equality (APE),

x^2-x-7=-7

Since it's a quadratic equation, it becomes

x^2-x=0

By factoring,

x(x-1)=0

Therefore,

x=0, or x=1.

I hope I've helped. :)