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How do I solve log7 0.915? Do not round until the final answer. Then round to four...
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The equation `(1/5)^x=17` needs to be solved for x, using the operation of logarithmation, hence, you need to take logarithms both sides, such that:
`ln (1/5)^x = ln 17`
You need to use the following logarithmic identity, such that:
`ln (a^x) = x*ln a`
Reasoning by analogy yields:
`x*ln (1/5) = ln 17 => x*(ln 5^(-1)) =- ln 17 => -x*(ln 5) = ln 17`
`x = -(ln 17)/(ln 5) => x =- 2.8332/1.6094`
`x = -1.7604`
Hence, evaluating the solution to the equation `(1/5)^x=17,` using logarithmation, yields `x = -1.7604.`
Posted by sciencesolve on June 6, 2013 at 3:46 PM (Answer #1)
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