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How do integrate function `int (3x^2)/e^(x^3) dx` ?
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You need to evaluate indefinite integral `int (3x^2)/(e^(x^3)) dx` using substitution such that:
`x^3 = y =gt 3x^2 dx = dy`
You need to change the variable such that:
`int (dy)/(e^(y)) = int e^(-y) dy `
`int e^(-y) dy = -e^(-y)+ c`
You need to substitute `x^3` for `y` such that:
`int (3x^2)/(e^(x^3)) dx = -e^(-x^3) + c`
Hence, evaluating the indefinite integral yields `int (3x^2)/(e^(x^3)) dx = -e^(-x^3) + c`
Posted by sciencesolve on August 21, 2012 at 12:16 PM (Answer #1)
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