# How do I determine the x-intercepts of f(x) = -5x² + 20x + 2?

### 2 Answers | Add Yours

`f(x)=-5x^2+20x+2`

To determine x-intercept, set f(x)=0.

`0=-5x^2+20x+2`

Then, use the quadratic formula to solve for x.

`x=[-b+-sqrt(b^2-4ac)]/(2a)= [-20+-sqrt((-20)^2-4(-5)(2))]/((-5)(2))= (-20+-2sqrt110)/(-10)`

`x_1= 2+sqrt110/5` and `x_2=2-sqrt110/5`

**Hence, the x-intercepts of `f(x)=-5x^2+20x+2` are `(2+sqrt110/5,0)` and `(2-sqrt110/5, 0)` .**

**Sources:**

(2 + √110/5, 0) and (2 - √**110**/5, 0)