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How to determine the antiderivative of the function x*arcsin x/square root(1-x^2)?

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loochy | Student

Posted May 11, 2011 at 3:50 PM via web

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How to determine the antiderivative of the function x*arcsin x/square root(1-x^2)?

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giorgiana1976 | College Teacher

Posted May 11, 2011 at 3:55 PM (Answer #1)

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To determine the antiderivative of a given function, we'll have to calculate the indefinite integral of that function.

We'll apply integration by parts. First, we'll recall the formula:

Int udv = u*v - Int vdu

Let u = arcsin x => du = dx/sqrt(1-x^2)

Let dv = xdx/sqrt(1-x^2) => v = -sqrt(1 - x^2)

Int x*arcsin x dx/sqrt(1-x^2) = -(arcsin x)*sqrt(1 - x^2) + Intsqrt(1 - x^2)dx/sqrt(1-x^2)

Int x*arcsin x dx/sqrt(1-x^2) = -(arcsin x)*sqrt(1 - x^2) + Int dx

Int x*arcsin x dx/sqrt(1-x^2) = -(arcsin x)*sqrt(1 - x^2) + x + C

The antiderivative of the given function f(x) is: F(x) = -(arcsin x)*sqrt(1 - x^2) + x + C.

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