How can I find the lim of (3 - x^2)/(x-3) as x approaches to 3?



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justaguide's profile pic

Posted on (Answer #1)

We need to find the value of lim x-->3 [ (3 - x^2)/(x - 3)]

Substitute x = 3, we get -6/0

We see that the denominator has a root at x = 3. Therefore the graph has a vertical asymptote at x = 3.

Also, for values of x > 3, (3 - x^2)/(x - 3) is negative and for values of x less than 3, the graph is positive. At x = 3, it does not have any value.

The required limit is not defined and cannot be found.

giorgiana1976's profile pic

Posted on (Answer #2)

To check if the function has limit, when x approaches to 3, we'll determine the lateral limit and the value of the function in accumulation point.

For x->3, x<3 (x approaches to 3, with values smaller than 3)

lim (3 - x^2)/(x-3) = -6/-0 = +infinite

For x->3, x>3 (x approaches to 3, with values higher than 3)

lim (3 - x^2)/(x-3) = -6/+0 = -infinite

Since the lateral limits are infinite and different, the limit of the function does not exist if x approaches to 3.

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