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A hot solution of potassium persulfate slowly decomposes, giving oxygen as one of the...

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lak-86 | Student, Undergraduate | Salutatorian

Posted June 12, 2013 at 7:51 PM via web

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A hot solution of potassium persulfate slowly decomposes, giving oxygen as one of the products as;

2K2S2O8+2H2O-->4KHSO4+O2

Calculate the maximum volume of oxygen gas that can be produced at 80C when a  solution  containing  0.100 mol  of  potassium  persulfate  decomposes  as  shown above. 
[At 80  °C 1 mol of oxygen has a volume of 29.0 dm3]

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted June 12, 2013 at 8:04 PM (Answer #1)

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`2K_2S_2O_8+ 2H_2Orarr4KHSO_4+O_2`

 

Mole ratio

`2K_2S_2O_8:O_2 = 2:1`

 

Amount of `2K_2S_2O_8` decomposed `= 0.1 mol`

Amount of `O_2` formed `= 0.1/2 = 0.05 mol`

 

It is given that the volume of 1 mol of `O_2` at 80C is `29dm^3` .

 

Volume of 0.05 moles of `O_2` at 80C `= 29xx0.05 = 1.45dm^3`

 

So the maximum volume of `O_2` that can be obtained by decomposing 0.1 mol of `2K_2S_2O_8 ` is `1.45dm^3` .

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