1 Answer | Add Yours
The Honda moving at 100 km/hr is 80 km behind a Ford moving in the same direction at 60 km/hr. The distance traveled by the Honda before it catches up with the Ford has to be determined.
Let the time taken by the Honda to catch up with the Ford be t. As the Ford is traveling at 60 km/h it moves a distance equal to 60*t in that duration. The distance moved by the Honda has to be 60*t + 80. As the Honda is moving at 100 km/h it moves a distance equal to 100*t
100*t = 60*t + 80
=> 40t = 80
=> t = 2
The distance traveled by the Honda is 100*2 = 200 km.
The Honda has to travel 200 km before it can catch up with the Ford.
We’ve answered 317,523 questions. We can answer yours, too.Ask a question