A hockey puck slides off the edge of a table with an initial velocity of 28.0 m/s. and experiences no air resistance. The height of the tabletop above the ground is 2.00 m. What is the angle below the horizontal of the velocity of the puck just before it hits the ground?

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During the flight of the hockey puck in air, the horizontal velocity remain unaltered, but the vertical velocity undergoes acceleration due to gravity.

Initial velocity: horizontal `= 28 ` m/s

Vertical `= 0` (free fall)

Final velocity: horizontal `=28` m/s

Vertical `=sqrt(2*g*h)=(sqrt2*9.81*2)=6.26` m/s

The relative final velociy of these two components would be their resultant:

`=sqrt(6.26^2+28^2)`

`=28.7 ` m/s

The angle `arctan(6.26/28)=12.6` degrees

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