# Herb has 13 toy cars. He keeps the cars in 2 cases. One has 3 more cars than the other case has. How many cars are in each case?

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Let the numbers of cars in the first case is x and the number of cars in the second car be y.

The total number of cars is 13.

==> Then we can write :

x+ y= 13

But we know that one has 3 more than the other.

==> y= x+3

Now we will plug in y= x+3 into the first equation.

==> x +(x+3) = 13

==> 2x = 10

==> x=5

==> y= 8

**Then, one case has 5 cars and the other has 8.**