Hemoglobin, the oxygen carrying protein in red blood cells, has four iron atoms per molecule and contains 0.340 percent iron by mass. Calculate...
...the molar mass of hemoglobin.
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The atomic mass of iron, according to the periodic chart, is 55.8g/mole.
Four atoms of iron is 223g/mole
223 = .34 x
x = 223/.34 = 656 g/mole
I forgot to convert 0.34% to a decimal. The equation should be:
223 = .0034 x
x = 65,600 g/mole
0.340 percent iron by mass means in 100g of haemoglobin there are 0.340 g of irons. and the molar mass of iron is 55.85 g/mol
and we know that there are 4 iron mole in a molecule of haemoglobin, so
(4 mol Fe/1 mol haemoglobin) * (55.85 g fe/ 1mol Fe)*(100 g of haemoglobin/0.340 g of Fe)
so the molar mass of haemoglobin is 65705.88 g/mol or 6.6*10^4 g/mol
now haemoglobin is a protein and the molar mass of protein is express in dalton (1 dalton = 1g/mol)
so the molar mass is 6.6*10^4 dalton.
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