How do I solve this?
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We have given
`` At maximum height , its velocity should be zero.
So differenciate with respect to t
Thus at t=3.47 sec , we have maximum height.
maximum height= -15.9 (3.47)^2+110.48(3.47)+3.02
The distance ball will have to cover after attaining maximum height ,before it catched= (194.47-6)
Substitute h=188.47 feet in given equation
Thus we have
solving the quadratic equation
`t=4.11 or 2.84`
To attained maximum height ball took 3.47 sec. so in returnjourney it should take less time tahn 3.47.
Thus t=2.84 sec.
Thus outfielder has to position himself for the catch if he intends to catch the ball =2.84+3.47=6.30 sec.
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