- Download PDF
I have some questions about physics?
2. A shopping cart given an initial velocity at 2.0 m/s East undergoes a constant acceleration of 3.0 m/s^2. What is the cart's displacement after the first 5.0s of its motion?
1 Answer | Add Yours
The formula for the displacement is
`d=v_0t + (at^2)/2` , where `v_0` is the initial velocity, a is the acceleration and t is the time elapsed from the beginning of the motion.
So after t = 5 s, assuming acceleration is in the same direction as the initial velocity (even though it is not really stated in the problem), the displacement will be
`d=2*5 + (3*5^2)/2 = 10+37.5 = 47.5` meters.
The displacement after 5 seconds of motion will be
d = 47.5 meters.
We’ve answered 327,708 questions. We can answer yours, too.Ask a question