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If I have 0.275 moles of a gas at a temperature of 75K and a pressure of 1.75 atm what...
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First of all we have to assume that this gas behaves as an ideal gas and hence we can apply the ideal gas law to this particular incident.
`PV = nRT`
`V = (nRT)/(P)`
here n = 0.275 mol
T= 75 K
P= 1.75 atm
and the gasconstant R = 0.082057 lit.atm/(K.mol)
`V = ((0.275 mol)(0.082057( l.atm)/(K.mol))(75K))/1.75 atm`
` ` V = 0.967 liters
Therefore the volume of the gas is 0.967 liters
Posted by malagala on May 21, 2012 at 6:08 PM (Answer #1)
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