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The equation of line L2 is 7x+4y-12 = 0.
Rewriting this in the slope intercept form `y = 12/4 - 7/4x` . The y-intercept of the line is (0, 3).
As the line L1 has the same y-intercept as L2 but the slope of the line is -4/5, its equation is: `y = (-4/5)x + 3`
=> 5y = -4x + 15
=> 4x + 5y - 15 = 0
The equation of L1 is 4x + 5y - 15 = 0
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