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It is given to you that 4x+10y=-26 is an equation of the tangent line to the graph of...
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at `x=16, ` the tangent curve intersect the graph of g therefore `y(16)=g(16).`
The slope of the tangent line is `g'(16)=-4/10=-2/5`
At `x=4, f'(4)=8g'(16)=-16/5`
An equation of the tangent line of y=g(x^2) at x=4 is `y=-16/5 (x-4)-9`
`y=-288/5 (x-16)+81 ` is an equation of the tangent line to `y=g^2(x) ` at `x=16`
Posted by cosinusix on March 21, 2012 at 2:17 PM (Answer #1)
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