Given y=sin(cosx) what is dy/dx?
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We'll have to differentiate the given function y with respect to x.
y = sin (cos x)
We'll differentiate both sides:
dy = [sin (cos x)]'dx
We'll differentiate using chain rule, since the given function is the result of composition of two functions:
dy/dx = [cos (cos x)]*(cos x)'
dy/dx = (-sin x)*[cos (cos x)]
The requested expression for dy/dx is: dy/dx = (-sin x)*[cos (cos x)].
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